Question: Fred is 4 years older than Barney. Five years ago the sum of their ages was 48. How old are they now?
Fred’s age: x + 4 (Because he is 4 years older than Barney)
Fred = x + 4 - 5 = x -1
2x - 6 = 48
2x = 48 + 6
x = 54/2 or 27
Fred = x + 4 = 27 + 4 = 31 now.
5 years ago, Fred was 31-5= 26
The sum of their ages was 22+26 = 48
Represent the AGES NOW:
Barney’s age: xFred’s age: x + 4 (Because he is 4 years older than Barney)
Represent the AGES five years ago:
Barney = x - 5Fred = x + 4 - 5 = x -1
Represent the equation:
Equation for the sum of their ages : x - 5 + x - 1 = 482x - 6 = 48
2x = 48 + 6
x = 54/2 or 27
ANSWER:
Barney is now 27.Fred = x + 4 = 27 + 4 = 31 now.
CHECK:
5 years ago, Barney was 27-5 = 225 years ago, Fred was 31-5= 26
The sum of their ages was 22+26 = 48
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